Respuesta :

Answer:

a) 0.1 lb/ft³

b) 20 lb

c) 88.788 N

Explanation:

Given:

Volume of the object = 200 ft³

Specific volume = 10 ft³/ lb

Now,

Density = [tex]\frac{\textup{1}}{\textup{Specific volume}}[/tex]

or

Density = [tex]\frac{1}{10}[/tex] = 0.1 lb/ft³

also,

Specific volume = [tex]\frac{\textup{Volume}}{\textup{Mass}}[/tex]

or

10 = [tex]\frac{200}{\textup{Mass}}[/tex]

or

Mass = 20 lb

And,

Weight =  Mass in kg × Acceleration due to gravity

Mass = 20 lb

and 1 lb = 0.453 kg

thus,

20 lb = 20 × 0.453 = 9.06 kg

Therefore,

weight = 9.06 × 9.8 = 88.788 N

For the object,

  • Density of the object is 0.1 ib per ft cubed
  • Mass of the object is 20 ib.
  • Weight of the object is 88.788 N

What is the specific volume of a object?

Specific volume of the object is inverse to the density of the object.

Given information-

The volume of the object is 200 ft cubed.

The specific volume of the object is 10 ft cubed.

The density of a object is the inverse of its specific volume, thus density of the given object is,

[tex]\rho=\dfrac{1}{\rm specific volume} \\\rho=\dfrac{1}{10} \\\rho=0.1 \rm ib/ft^3[/tex]

The mass of a object is the ratio of the volume to the specific volume, thus mass of the given object is,

[tex]m=\dfrac{\rm volume}{\rm specific volume} \\m=\dfrac{200}{10} \\m=20 \rm ib[/tex]

As 1 Ib is equal to the 0.453 kg.

The weight of a object is the product of the mass of the object to the acceleration due to gravity, thus weight of the given object is,

[tex]W=0.453\times20\times9.81\\W=88.788\rm N[/tex]

Thus for the object,

  • Density of the object is 0.1 ib per ft cubed
  • Mass of the object is 20 ib.
  • Weight of the object is 88.788 N

Learn more about the specific density here;

https://brainly.com/question/24799156

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