Answer:
5953.42 J
Explanation:
Given:
Initial volume, [tex]V_i[/tex]= 100 in³
Final Volume, [tex]V_f[/tex] = 10 in³
Initial pressure = 50 psia
Temperature = 100° F = 310.93 K
For isothermal reversible process, work done is given as:
Work done = [tex]-2.303RTlog_{10}\frac{V_f}{V_i}[/tex]
Where,
R is the ideal gas constant = 8.314 J/mol.K
or
Work done = [tex]-2.303\times8.314\times310.93log_{10}\frac{10}{100}[/tex]
or
Work done = 5953.42 J
