Answer:
6.82% is the mass percent NaOH in the solution.
Explanation:
Mass of the solute that is NaOH = m = 20 g
Mass of the solution = M
Volume of the solution = V = 255 mL
Density of the solution = d = 1.15 g/mL
[tex]Density=\frac{Mass}{Volume}[/tex]
[tex]1.15 g/mL=\frac{M}{255 mL}[/tex]
M = 293.25 g
Mass percentage of solute :(w/w)%
[tex]\frac{m}{M}\times 100[/tex]
[tex](w/w)\%=\frac{20 g}{293.25 g}\times 100=6.82\%[/tex]
6.82% is the mass percent NaOH in the solution.