Answer:
The flux of the electric field is 677.6 Nm²/C
Explanation:
Given that,
Area = 18 cm²
Charge = 6.0 nC
We need to calculate the flux of the electric field
Using Gauss's law
[tex]\phi=\dfrac{q}{\epsilon_{0}}[/tex]
Where, q = charge
[tex]\epsilon_{0}[/tex] =permittivity of free space
Put the value into the formula
[tex]\phi=\dfrac{6.0\times10^{-9}}{8.854\times10^{-12}}[/tex]
[tex]\phi=677.6\ Nm^2/C[/tex]
Hence, The flux of the electric field is 677.6 Nm²/C.
