contestada

Radon-219 decays to radon-218 by releasing... a. a positron b.a muon O c. a neutron O d. an electron O e. a proton

Respuesta :

Answer: Option (c) is the correct answer.

Explanation:

A positron is denoted as [tex]^{0}_{+1}e[/tex], a neutron is denoted as [tex]^{1}_{0}n[/tex], an electron is denoted as [tex]^{0}_{-1}e[/tex], and a proton is denoted as [tex]^{1}_{1}p[/tex].

Therefore, when [tex]^{219}Rn[/tex] will decay into [tex]^{218}Rn[/tex] this means there occurs decrease in its mass number. Hence, it means a neutron will be releasing during this reaction.

The reaction will be as follows.

                [tex]^{219}Rn \rightarrow ^{218}Rn + ^{1}_{0}n[/tex]