Answer:
Option d, Amount left = 16 μg
Explanation:
Half life = 88 days
Initial concentration = 128 μg
[tex]No.\ of\ half\ life=\frac{Total\ days}{t_{1/2}}[/tex]
[tex]No.\ of\ half\ life=\frac{264}{88} = 3[/tex]
Amount of material left after n half life = [tex]\frac{Amount\ of\ starting\ material}{2^n}[/tex]
Where, n = No. of half life
Amount of material left = [tex]\frac{128}{2^3}[/tex]
= [tex]\frac{128}{8} = 16[/tex]μg
SO, option d is correct
