Answer:
The total force exerted on the Y axis is: -52.07μC
Explanation:
This is an electrostatic problem, so we will use the formulas from the Coulomb's law:
[tex]F=k*\frac{Q*Q'}{r^2}\\where:\\k=coulomb constant\\r=distance\\Q=charge[/tex]
We are interested only of the effect of the force on the Y axis. We can notice that the charge placed on the x=4cm will exers a force only on the Y axis so:
[tex]Fy1=9*10^9*\frac{6.05*10^{-9}*(-1.97)*10^{-9}}{(3.02*10^{-2})^2}\\[/tex]
Fy1=-117.61μC
For the charge placed on the origin we have to calculate the distance and the angle:
[tex]r=\sqrt{(4*10^{-2}m)^2 +(3.02*10^{-2}m)^2} \\r=5cm=0.05m[/tex]
we can find the angle with:
[tex]alpha = arctg(\frac{3.02cm}{4cm})=37^o[/tex]
The for the Force on Y axis is:
[tex]Fy2=9*10^9*\frac{6.05*10^{-9}*(5)*10^{-9}}{(3.02*10^{-2})^2}*sin(37^o)\\[/tex]
Fy2=65.54μC
The total force exerted on the Y axis is:
Fy=Fy1+Fy2=-52.07μC
