Answer:
distance between both oasis ( 1 and 2) is 27.83 Km
Explanation:
let d is the distance between oasis1 and oasis 2
from figure
OC = 25cos 30
OE = 25sin30
OE = CD
Therefore BC = 30-25sin30
distance between both oasis ( 1 and 2) is calculated by using phytogoras theorem
in[tex]\Delta BCO[/tex]
[tex]OB^2 = BC^2 + OC^2[/tex]
PUTTING ALL VALUE IN ABOVE EQUATION
[tex]d^2 = 930-25sin30)^2 + (25cos30)^2[/tex]
[tex]d^2 = 775[/tex]
d = 27.83 Km
distance between both oasis ( 1 and 2) is 27.83 Km
