Answer:22.76 m/s
Explanation:
Given
Train length(L)=75 m
Front of train after travelling 125 m is 18 m/s
Time taken by the front of train to cover 125 m
[tex]v^2-u^2=2as[/tex]
[tex]18^2-0=2\times a\times 125[/tex]
[tex]a=1.296 m/s^2[/tex]
Speed of the last part of train when it passes the worker i.e. front of train has to travel has to travel a distance of 125+75=200 m
[tex]v^2-u^2=2as[/tex]
[tex]v^2=2\times 1.296\times 200[/tex]
[tex]v=\sqrt{518.4}=22.76 m/s[/tex]
