Explanation:
Given that,
Charge 1, [tex]q_1=7.8\ nC=7.8\times 10^{-9}\ C[/tex]
Charge 2, [tex]q_2=4.3\ nC=4.3\times 10^{-9}\ C[/tex]
Distance between charges, r = 1.81 m
(a) The electrostatic force that one charge exerts on the another is given by :
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]
[tex]F=9\times 10^9\times \dfrac{7.8\times 10^{-9}\times 4.3\times 10^{-9}}{(1.81)^2}[/tex]
[tex]F=9.21\times 10^{-8}\ N[/tex]
(b) As both charges are positively charged. So, the force of attraction between them is repulsive.
