Answer:7 cm
Explanation:
Given
one sphere has a radius(r) of 4.85 cm
Also another sphere has a mass 3 times the previous one
since the density remains same therefore
second sphere has a volume 3 times of former.
Let R be the radius of bigger Sphere
[tex]\frac{4\pi R^3}{3}=3\times \frac{4\pi r^3}{3}[/tex]
[tex]R=\left ( 3\right )^\frac{1}{3}r=1.44\times 4.85=6.99 \approx 7 cm[/tex]
