Respuesta :
Answer:
Least velocity.
Explanation:
According to the Bernauli's equation
[tex]p^{2}+\frac{1}{2}\rho v^{2}+\rho gh= constant[/tex]
Here, v is the velocity, m is the mass, h is the height, P is the pressure, [tex]\rho[/tex] is the density
Now according to question.
[tex]P_{1}^{2}+\frac{1}{2}\rho v_{1} ^{2}+\rho gh_{1} =P_{2}^{2}+\frac{1}{2}\rho v_{2} ^{2}+\rho gh_{2}[/tex]
Here airplane height is same means [tex]h_{1}=h_{2}[/tex] then the required equation will become.
[tex]P_{1}^{2}+\frac{1}{2}\rho v_{1} ^{2}=P_{2}^{2}+\frac{1}{2}\rho v_{2} ^{2}[/tex]
Therefore,
[tex]P_{1}-P_{2}=\frac{1}{2}\rho (v_{2} ^{2}-v_{1} ^{2})[/tex]
Therefore according to the situation [tex]P_{1}>P_{2}[/tex]
This will give the velocity relation [tex]v_{2} >v_{1}[/tex]
Therefore, airplane can fly with least velocity.
