Answer: The density of the metal is 10.60 g/mL and the volume occupied by 86.0 grams is 8.11 mL
Explanation:
To calculate the density of unknown metal, we use the equation:
[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex] ......(1)
Volume of unknown metal = 19.8 mL
Mass of unknown metal = 210.0 g
Putting values in equation 1, we get:
[tex]\text{Density of unknown metal}=\frac{210.0g}{19.8mL}\\\\\text{Density of unknown metal}=10.60g/mL[/tex]
The density of the metal remains the same.
Now, calculating the volume of unknown metal, using equation 1, we get:
Density of unknown metal = 11.45 /mL
Mass of unknown metal = 86.0 g
Putting values in above equation, we get:
[tex]10.60g/mL=\frac{86.0g}{\text{Volume of unknown metal}}\\\\\text{Volume of unknown metal}=8.11mL[/tex]
Hence, the density of the metal is 10.60 g/mL and the volume occupied by 86.0 grams is 8.11 mL
