Answer:
(a). The displacement is 3.11 m.
(b). The average velocity is 2.42 km/hr.
Explanation:
Given that,
A bird watcher meanders through the woods, walking 1.46 km due east, 0.123 km due south, and 4.24 km in a direction 52.4° north of west.
(a). We need to calculate the displacement
Using Pythagorean theorem
[tex]D=\sqrt{(OA)^2+(AB)^2}[/tex]
[tex]D=\sqrt{(1.46-4.24\sin52.4)^2+(0.123-4.24\cos52.4)^2}[/tex]
[tex]D=3.11\ km[/tex]
(b). We need to calculate the average velocity
Using formula of average velocity
[tex]v_{avg}=\dfrac{D}{T}[/tex]
Where, D = displacement
T = time
Put the value into the formula
[tex]v_{avg}=\dfrac{3.11}{1.285}[/tex]
[tex]v_{avg}=2.42\ km/hr[/tex]
Hence, (a). The displacement is 3.11 m.
(b). The average velocity is 2.42 km/hr.
