Answer: The values of 'x' are 0.074 and -0.132
Explanation:
The equation given to us is:
[tex]\frac{x^2}{0.160-x}=0.058[/tex]
Rearranging the above equation, we get a quadratic equation:
[tex]x^2+0.058x-0.009744=0[/tex]
To solve this equation, we use quadratic formula, which is:
[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
where,
a = coefficient of [tex]x^2[/tex] = 1
b = coefficient of x = 0.058
c = constant = 0.009744
Putting values in above equation, we get:
[tex]x=\frac{-0.058\pm \sqrt{(0.058)^2-4(1)(0.009744)}}{2\times 1}\\\\x=0.074,-0.132[/tex]
Hence, the values of 'x' are 0.074 and -0.132
