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Two identical small insulating balls are suspended by separate 0.26-m threads that are attached to a common point on the ceiling. Each ball has a mass of 7.75 10^-4 kg. Initially the balls are uncharged and hang straight down. They are then given identical positive charges and, as a result, spread apart with an angle of 35° between the threads. (a) Determine the charge on each ball. (answer in C)

Respuesta :

Answer:

charge on each ball is 8.07 *10{-8} C

Explanation:

given data:

L = 0.26 m

m = 7.75 *10^-4 Kg

[tex]\theta = \frac{35}{2} degree = 17.5 degree[/tex]

let charge on each ball  is q

let tension in the string is T

so force will be

T\times cos(17.5) = mg

[tex]T\times sin(17.5) =\frac{kq^2}{(2Lsin(17.5))^2}[/tex]

[tex]T \times cos(17.5 degree) = 7.75 *10^{-4}\times 9.8[/tex]                                     ----(1)

[tex]T\times sin(17.5 degree) = \frac{9 *10^9 * (q)^2}{(2 * 0.26 sin(17.5 degree))^2}[/tex] ---(2)

solving 1 and 2  for Tension T  and charge  q   we get

T = 0.00796 N

[tex]    q = 8.07 *10^{-8} C[/tex]    

charge on each ball is 8.07 *10{-8} C

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