Answer:
22.27 m
Explanation:
initial velocity, u = 25 m/s
Angle of projection, θ = 45°
height, h = 30 m
Let t be the time taken to reach the ground.
use second equation of motion in vertical direction
[tex]s = ut + \frac{1}{2}at^{2}[/tex]
[tex]- 30 = -25 Sin 45\times t - \frac{1}{2}\times 9.8t^{2}[/tex]
[tex]4.9t^{2}+17.67 t - 30 = 0[/tex]
[tex]t=\frac{-17.67\pm \sqrt{17.67^{2}+4\times 4.9 \times 30}}{9.8}[/tex]
t = 1.26 second
The horizontal distance = horizontal velocity x time
d = 25 Cos 45 x 1.26 = 22.27 m
