Answer:
Speed of ball equals 6.024 m/s.
Explanation:
Let the student throw the ball with a velocity of 'v' m/s horizontally.
Now the time in which the ball travels 10.0 meter horizontally shall be equal to the time in which it travels (15.0-1.50) meters vertically
Hence the time taken to cover a vertical distance of 13.50 meters is obatined using 2 equation of kinematics as
[tex]s=\frac{1}{2}gt^{2}\\\\t=\sqrt{\frac{2s}{g}}\\\\t=\sqrt{\frac{2\times 13.5}{9.81}}\\\\\therefore t=1.66 seconds[/tex]
Since there is no acceleration in horizantal direction we infer that in time of 1.66 seconds the ball travels a distance of 10 meters
Hence the spped of throw is obatines as
[tex]Speed=\frac{Distance}{Time}\\\\v=\frac{10}{1.66}=6.024m/s[/tex]
