Answer:
ΔH = - 36.3 kJ
Explanation:
The given chemical reaction is as follows -
H₂ (s) + Br₂ (g) ------> 2HBr (s) + 36.3 kJ
In the above equation , the amount of energy i.e. 36.3 kJ is released , i.e. it is in the product side , hence , the reaction is an example of an exothermic reaction .
Hence ,
The value of the change in enthalphy , i.e. , the enthalpy of product minus the enthalpy of the product .
Therefore ,
The value of the change in enthalphy = - ve .
Hence ,
ΔH = - 36.3 kJ