Answer:
The acceleration of proton will be [tex]431.137\times 10^8m/sec^2[/tex]
Explanation:
We have given electric field E = 450 N/C
Charge on proton [tex]=1.6\times 10^{-19}C[/tex]
Force on electron due to electric field is given by [tex]F=qE=1.6\times 10^{-19}\times 450=720\times 10^{-19}N[/tex]
Mass of electron [tex]m=1.67\times 10^{-27}kg[/tex]
Now according to second law of motion [tex]F=ma[/tex]
So [tex]720\times10^{-19}=1.67\times 10^{-27}a[/tex]
[tex]a=431.137\times 10^8m/sec^2[/tex]
So the acceleration of proton will be [tex]431.137\times 10^8m/sec^2[/tex]
