Answer:
[tex]E=1.56\times 10^{23}\ N/C[/tex]
Explanation:
Given that,
Electric force applied to the electron, [tex]F=25000\ N[/tex]
Charge on electron, [tex]q=1.6\times 10^{-19}\ C[/tex]
We need to find the electric force acting on the electron. The electric field is given by :
[tex]E=\dfrac{F}{q}[/tex]
[tex]E=\dfrac{25000}{1.6\times 10^{-19}}[/tex]
[tex]E=1.56\times 10^{23}\ N/C[/tex]
So, the electric field acting on the electron is [tex]1.56\times 10^{23}\ N/C[/tex]. Hence, this is the required solution
