Respuesta :
Answer: a) 0.08157 moles of [tex]Al^{3+}[/tex]
b) 0.24471 moles of [tex]ClO_4^{-}[/tex]
c) 0.97884 moles of oxygen atoms
Explanation:-
The dissociation of the given compound is shown by the balanced equation:
[tex]Al(ClO_4)_3\rightarrow Al^{3+}+3ClO_4^{-}[/tex]
According to stoichiometry:
a) 1 mole of [tex]Al(ClO_4)_3[/tex] produces 1 mole of [tex]Al^{3+}[/tex]
Thus 0.08157 mole of [tex]Al(ClO_4)_3[/tex] produces=[tex]\frac{1}{1}\times 0.08157=0.08157moles[/tex] of [tex]Al^{3+}[/tex]
b) 1 mole of [tex]Al(ClO_4)_3[/tex] produces 3 moles of [tex]ClO_4^{-}[/tex]
Thus 0.08157 mole of [tex]Al(ClO_4)_3[/tex] produces=[tex]\frac{3}{1}\times 0.08157=0.24471moles[/tex] of [tex]ClO_4^{-}[/tex]
c) 1 mole of [tex]Al(ClO_4)_3[/tex] produces 12 moles of oxygen atoms
Thus 0.08157 mole of [tex]Al(ClO_4)_3[/tex] produces=[tex]\frac{12}{1}\times 0.08157=0.97884moles[/tex] of oxygen atoms
