Answer:
Explanation:
Given
Cheetah speed=21.8 m/s in 2.55 sec
i.e. its [tex]a=\frac{21.8}{2.55}=8.55 m/s^2[/tex]
Cheetah top speed=28.1 m/s
And 1 m/s is equal to 2.23694 mph
therefore 28.1 m/s is [tex]2.236\times 28.1=62.858 mph[/tex]
Time taken to reach top speed
v=u+at
[tex]28.1=0+8.55\times t[/tex]
[tex]t=\frac{28.1}{8.55}=3.286 s [/tex]
Distance traveled during this time
[tex]v^2-u^2=2as[/tex]
[tex]28.1^2=2\times 8.55\times s[/tex]
[tex]s=\frac{789.61}{2\times 8.55}=46.176 m[/tex]
If cheetah sees a rabbit 122 m away
time taken to reach rabbit
[tex]s=ut+\frac{1}{2}at^2[/tex]
[tex]122=0+\frac{1}{2}\times 8.55\times t^2[/tex]
[tex]t^2=\frac{244}{8.55}[/tex]
[tex]t=\sqrt{28.53}=5.34 s[/tex]
