Respuesta :
Answer:
[tex]1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}[/tex]
Step-by-step explanation:
To find : Convert [tex]1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}[/tex] into [tex]\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}[/tex]
Solution :
We convert units one by one,
[tex]1\text{ m}^2=10.7639\text{ ft}^2[/tex]
[tex]1\text{ sec}=\frac{1}{3600}\text{ hour}[/tex]
[tex]1\text{ cal}=0.003968\text{ BTU}[/tex]
Converting temperature unit,
[tex]^\circ C\times \frac{9}{5}+32=^\circ F[/tex]
[tex]1^\circ C\times \frac{9}{5}+32=33.8^\circ F[/tex]
So, [tex]1^\circ C=33.8^\circ F[/tex]
Substitute all the values in the unit conversion,
[tex]1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}[/tex]
[tex]1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}[/tex]
[tex]1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}[/tex]
Therefore, The conversion of unit is [tex]1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}[/tex]
