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An owl fiying at 30 m/s emits a cry whose frequency is 540 Hz. A mockingbird is moving in the same direction as the owl at 14 m/s. (Assume the speed of sound is 343 m/s. (a) What frequency does the mockingbird hear (in Hz) as the owl approaches the mockingbird? (b) What frequency does the mockingbird hear (in Hz) after the owl passes the mockingbind?

Respuesta :

lcmendozaf

Answer:

a) 567.6Hz

b) 516.8Hz

Explanation:

Using the formula for doppler effect:

[tex]f=\frac{C - V_{m} }{C - V_{o}} *f_{o}[/tex]   where:

[tex]V_{m}=15m/s; V_{o} = 30m/s; f_{o}=540Hz; C=343m/s[/tex]

Replacing the values we get:

f=567.6Hz

After the owl passes the mockingbind, the direction of sound relative to the owl and mockingbind changes direction, so the equation will be:

[tex]f=\frac{C + V_{m} }{C + V_{o}} *f_{o}[/tex]

Replacing the values we get:

f=516.8Hz

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