Answer:
The magnitude of the resultant vector is 13.656 units.
Explanation:
The vector A can be represented vectorially as
[tex]\overrightarrow{r}_{a}=6.00\widehat{i}-4.40\widehat{j}[/tex]
Similarly vector B can be represented vectorially as
[tex]\overrightarrow{r}_{b}=3.30\widehat{i}-5.60\widehat{j}[/tex]
Thus upon adding the 2 vectors we get
[tex]\overrightarrow{r}_{a}+\overrightarrow{r}_{b}=6.00\widehat{i}-4.40\widehat{j}+3.30\widehat{i}-5.60\widehat{j}\\\\=(6.00+3.30)\widehat{i}-(4.40+5.60)\widehat{j}\\\\=9.30\widehat{i}-10.00\widehat{j}[/tex]
Now the magnitude of the vector is given by:
|r|=[tex]\sqrt{x^{2}+y^{2}}\\\\|r|=\sqrt{9.30^{2}+(-10)^{2}}\\\\\therefore |r|=13.65units[/tex]
