Answer:4.95 m/s
Explanation:
Given
Ball rises to a height of 1.25 m
Let u be the velocity of player while leaving ground .
Its final velocity will be zero as he reaches a height of 1.25 m
thus
[tex]u^2=2gh[/tex]
[tex]u=\sqrt{2\times 9.81\times 1.25}[/tex]
[tex]u=\sqrt{24.525}[/tex]
u=4.952 m/s