Answer:
6.88 mA
Explanation:
Given:
Resistance, R = 594 Ω
Capacitance = 1.3 μF
emf, V = 6.53 V
Time, t = 1 time constant
Now,
The initial current, I₀ = [tex]\frac{\textup{V}}{\textup{R}}[/tex]
or
I₀ = [tex]\frac{\textup{6.53}}{\textup{594}}[/tex]
or
I₀ = 0.0109 A
also,
I = [tex]I_0[1-e^{-\frac{t}{\tau}}][/tex]
here,
τ = time constant
e = 2.717
on substituting the respective values, we get
I = [tex]0.0109[1-e^{-\frac{\tau}{\tau}}][/tex]
or
I = [tex]0.0109[1-2.717^{-1}][/tex]
or
I = 0.00688 A
or
I = 6.88 mA