Answer:
184.6 BTU
Explanation:
The thermal efficiency for a Carnot cycle follows this equation:
η = 1 - T2/T1
Where
η: thermal efficiency
T1: temperature of the heat source
T2: temperature of the heat sink
These temperatures must be in absolute scale:
1000 F = 1460 R
50 F = 510 R
Then
η = 1 - 510/1460 = 0.65
We also know that for any heat engine:
η = L / Q1
Where
L: useful work
Q1: heat taken from the source
Rearranging:
Q1 = L / η
Q1 = 120 / 0.65 = 184.6 BTU
In this exercise we will deal with the Carnot cycle and calculate how much heat was initially placed, so we have that:
The heat input to the engine was 184.6 BTU
The theoretical Carnot cycle is formed by two isothermal transformations and two adiabatic transformations. One of the isothermal transformations is used for the temperature of the hot source, where the expansion process takes place, and the other for the cold source, where the compression process takes place.
The thermal efficiency for a Carnot cycle follows this equation:
[tex]\eta= 1 - T_2/T_1[/tex]
Where:
These temperatures must be in absolute scale:
[tex]\eta = 1 - 510/1460 = 0.65[/tex]
Rearranging:
[tex]Q_1 = L / \eta\\Q_1 = 120 / 0.65 = 184.6 BTU[/tex]
See more about carnot cycle at brainly.com/question/21126569
