Answer:
a) -2 from (-2,0) b) 6 from (6,0) c) y-intercept: 12 from (0,12)
Step-by-step explanation:
The X intercepts in a quadratic function are the points of the x-axis crossed by the parabola. One quadratic equation may have up to two points on the X-axis. This or these points in the X-axis, the Zeros of this function, will be crossed by the parabola.
The Y-intercept is the point of the y-axis crossed by the parabola.
Solving the equation:
[tex]-x^{2} +4x+12=0\\ x'=\frac{-4+\sqrt{64}}{-2} \\ x"=\frac{-4-\sqrt{64}}{-2} \\ x'=-2\\ x"=6\\[/tex]
S={-2, 6} These values, or zeros of this quadratic function are the X, intercepts.
c) The indepent term, or c, in f(x)= ax²+bx+c in this case is 12, also is the Y coordinate for the Parabola Vertex. This point is our intercept for y.
