Answer:
[tex]\text{Customer that bought only one paper}=33[/tex]
[tex]\text{Customer that bought something other than either of the two papers}=7[/tex]
Step-by-step explanation:
We have been given that at a newsstand, out of 46 customers, 27 bought the Daily News, 18 bought the Tribune, and 6 bought both papers.
[tex]\text{Customer that bought only Daily news}=27-6[/tex]
[tex]\text{Customer that bought only Daily news}=21[/tex]
[tex]\text{Customer that bought only Tribune}=18-6[/tex]
[tex]\text{Customer that bought only Tribune}=12[/tex]
The customer that bought only one paper would be the sum of customers, who bought only Daily news or Tribune.
[tex]\text{Customer that bought only one paper}=21+12[/tex]
[tex]\text{Customer that bought only one paper}=33[/tex]
Therefore, 33 customers bought only one paper.
[tex]\text{Customer that bought something other than either of the two papers}=46-(27+18-6)[/tex]
[tex]\text{Customer that bought something other than either of the two papers}=46-(45-6)[/tex]
[tex]\text{Customer that bought something other than either of the two papers}=46-39[/tex]
[tex]\text{Customer that bought something other than either of the two papers}=7[/tex]
Therefore, 7 customers bought something other than either of the two papers.
