contestada

A 2000 kg car rounds a circular turn of radius 20 m. If
theroad is flat and the coefficient of friction between tires and
roadis 0.70, how fast can the car go without skidding?

Respuesta :

Answer:

The velocity of car is 11.71 m/s.

Explanation:

Given that,

Mass of car = 2000 kg

Radius = 20 m

Coefficient of friction = 0.70

We need to calculate the velocity of car

Using relation centripetal force and frictional force

[tex]F= \dfrac{mv^2}{r}[/tex]...(I)

[tex]F=\mu mg[/tex]...(II)

From equation (I) and (II)

[tex]\dfrac{mv^2}{r}=\mu mg[/tex]

[tex]v=\sqrt{\mu\times r\times g}[/tex]

Put the value into the formula

[tex]v=\sqrt{0.70\times20\times9.8}[/tex]

[tex]v=11.71\ m/s[/tex]

Hence, The velocity of car is 11.71 m/s.

Answer:

car can move at  11 m/s without skidding.

Explanation:

given,

mass of car = 2000 kg

radius of turn = 20 m

μ = 0.7

using centripetal force

F = [tex]\dfrac{mV^2}{R}[/tex].....................(1)

and we know                                

F = μ N  = μ m g........................(2)

equating both the equation (1) and (2)                        

μ m g = [tex]\dfrac{mV^2}{R}[/tex]

v = [tex]\sqrt{\mu R g}[/tex]                                

v = [tex]\sqrt{0.7 \times 20 \times 9.81}[/tex]

v = 11.71 m/s                                            

hence, car can move at  11 m/s without skidding.