If $1600 earned simple interest of $56.24 in 2 months, what was the simple interest rate? The simple interest rate is % (Do not round until the final answer. Then round to the nearest tenth as needed.)

Respuesta :

Answer:

[tex]\$21.1[/tex]

Step-by-step explanation:

We know that for principal amount P , time period T and rate of interest [tex]R\%[/tex] , simple interest is given by [tex]S.I. = \frac{P\times R\times T}{100}[/tex] .

Here ,

[tex]P=\$1600\\T=2\,\,months=\frac{2}{12}\,\,years=\frac{1}{6}\,\,years\\S.I=\$56.24[/tex]

To find :  simple interest rate i.e., [tex]R\%[/tex]

On putting values of [tex]P\,,\,T\,,\,S.I[/tex] in formula , we get [tex]S.I. = \frac{P\times R\times T}{100}[/tex]

[tex]56.24 = \frac{1600\times R\times 1}{600}\\R=\frac{56.24\times 600 }{1600}=\frac{703\times 3}{100}=\$21.09[/tex]

Now we need to round off the answer to the nearest tenth .

So, simple interest rate is % = [tex]\$21.09[/tex] = [tex]\$21.1[/tex]