Answer:
The air mass in the tank is 23.78 kg
Solution:
As per the question:
Volume of the tank, [tex]V_{t} = 200 l = 2\times 10^{- 3} m^{3}[/tex]
Pressure, P = 1 MPa = [tex]1\times 10^{6} Pa[/tex]
Temperature, T = [tex]20^{\circ}C[/tex] = 273 + 20 = 293 K
Pressure, P' = 0.5 MPa = [tex]0.5\times 10^{6} Pa[/tex]
Now,
To calculate the air mass, [tex]m_{a}[/tex] we use:
[tex]PV_{t} = m_{a}RT[/tex]
where
R = Rydberg constant = 0.287 J/kg.K
[tex]1\times 10^{6}\times 2\times 10^{- 3} = m_{a}0.287\times 293[/tex]
[tex]m_{a} = 23.78 kg[/tex]
