Answer:
The 105th term of given sequence is [tex]\frac{105}{2}[/tex].
Step-by-step explanation:
The given sequence is
[tex]\frac{1}{2},1,\frac{3}{2},2[/tex]
It can be rewritten as
[tex]0.5,1,1.5,2[/tex]
Here the first term is 0.5.
It is an arithmetic sequence because it has common difference.
[tex]d=a_2-a_1=1-0.5=0.5[/tex]
[tex]d=a_3-a_2=1.5-1=0.5[/tex]
[tex]d=a_4-a_3=2-1.5=0.5[/tex]
The nth term of an AP is
[tex]a_n=a_1+(n-1)d[/tex]
where, [tex]a_1[/tex] is first term and d is common difference.
Substitute [tex]a_1=0.5[/tex] and [tex]d=0.5[/tex] in the above formula.
[tex]a_n=0.5+(n-1)0.5[/tex]
[tex]a_n=0.5+0.5n-0.5[/tex]
[tex]a_n=0.5n[/tex]
We need to find the 105th term of given sequence.
Substitute n=105 in the above equation.
[tex]a_n=0.5(105)[/tex]
[tex]a_n=52.5[/tex]
[tex]a_n=\frac{105}{2}[/tex]
Therefore the 105th term of given sequence is [tex]\frac{105}{2}[/tex].