Answer:
Her adjusted body weight is 78.26kg = 78.3kg, rounded to the nearest tenth.
Step-by-step explanation:
To find the Adjusted Body Weight(AjBW), first we have to consider the Ideal Body Weight(IBW).
We have the following formulas:
[tex]IBW = 45.5kg + 2.3kg*i[/tex], in which i is the number of inches that the woman has above 5 feet.
[tex]AjBW = IBW + 0.4*(ABW - IBW)[/tex], in which [tex]ABW[/tex] is her Actual Body Weight
So, in this problem:
Each pound has 0.45kg. So her weight is [tex]ABW = 220*0.45 = 99.8[/tex]kg.
The woman is 8 inches above 5 feet, so [tex]i = 8[/tex].
[tex]IBW = 45.5 + 2.3*8[/tex]
[tex]IBW = 63.9[/tex]kg
Her ideal body weight is 63.9kg. Her adjusted body weight is:
[tex]AjBW = IBW + 0.4*(ABW - IBW)[/tex]
[tex]AjBW = 63.9 + 0.4*(99.8-63.9)[/tex]
[tex]AjBw = 78.26[/tex]kg
Her adjusted body weight is 78.26kg = 78.3kg.
