Answer:
Power in kW is 104 kW
Power in horsepower is 139.41 hp
Solution:
As per the question:
Velocity of the airplane, [tex]v_{a} = 80 m/s[/tex]
Force exerted by the propeller, [tex]F_{p} = 1300 N[/tex]
Now,
The useful power that the propeller delivered, [tex]P_{p}[/tex]:
[tex]P_{p} = \frac{Energy}{time, t}[/tex]
Here, work done provides the useful energy
Also, Work done is the product of the displacement, 'x' of an object when acted upon by some external force.
Thus
[tex]P_{p} = \frac{F_{p}\times x}{time, t}[/tex]
[tex]P_{p} = \frac{F_{p}\times x}{time, t}[/tex]
[tex]P_{p} = F_{p}\times v_{a}[/tex]
Now, putting given values in it:
[tex]P_{p} = 1300\times 80 = 104000 W = 104 kW[/tex]
In horsepower:
1 hp = 746 W
Thus
[tex]P_{p} = \frac{104000}{746} = 139.41 hp[/tex]
