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A skiy diver, with parachute unopened, falls 625 m in 15.0s.
Then she opens her parachute and falls another 356 m in142 s. What
is her average velocity (both magnitude anddirection) for the
entire fall?

Respuesta :

Answer:

average velocity = 6.25m/sec

Explanation:

given data:

for unopened

height = 625 m

time  = 15 sec

for opened

height = 356 m

time =  142 sec

Unopened:

[tex]V1 = \frac{625\ m}{15\ sec} = 41.67m/sec[/tex]

Opened:

[tex]V2 = \frac{356\ m}{142\ sec} = 2.51m/sec[/tex]

we know that

Total Average Velocity[tex] = \frac{Total\ distance}{Total\ time}[/tex]

average velocity[tex] = \frac{981\ m}{157\ sec}[/tex]

average velocity = 6.25m/sec

downward direction.

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