A 11400 kg lunar landing craft is about to touchdown on the
surface of the moon. acceleration due to gravity onmoon is 1.0
m/s2. At an altitude of 165 m the craft's downwardvelocity is 18.0
ms . To slow down the craft, a retrorocket isfired to provide an
upward thrust. Assuming the descent isvertical, find the magniturde
of the trhust needded to reduce thevelocity to zero at the instant
when the craft touches the lunarsurface.

Respuesta :

Answer:

F = 22572N

Explanation:

We will first calculate the acceleration needed to achieve landing speed equals zero:

[tex]V_{f}^{2}=V_{o}^{2}+2*a*\Delta Y[/tex]

[tex]0=18^{2}+2*a*(-165)[/tex]   Solving for a:

[tex]a=0.98 m/s^{2}[/tex]

Now that we have the required acceleration, we need to check all forces acting on the craft:

[tex]F_{thrust} - W = m*a[/tex]   where W = 11400N; m = 11400Kg; a = 0.98m/s2

Solving the equation:

[tex]F_{thrust}=22572N[/tex]