Answer:
[tex]F=1.07\times 10^{-3}\ N[/tex]
Explanation:
Given that,
Charge on two balls, [tex]q_1=q_2=-38\ nC=-38\times 10^{-9}\ C[/tex]
Distance between charges, r = 11 cm = 0.11 m
We need to find the repulsive force between balls. Mathematically, it is given by :
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]
[tex]F=9\times 10^9\times \dfrac{(38\times 10^{-9})^2}{(0.11)^2}[/tex]
F = 0.001074 N
or
[tex]F=1.07\times 10^{-3}\ N[/tex]
So, the magnitude of repulsive force between the balls is [tex]1.07\times 10^{-3}\ N[/tex].
