Answer:
[tex]\frac{5}{36}[/tex]
Step-by-step explanation:
Given,
P(A) = [tex]\frac{1}{2}[/tex],
P(B) = [tex]\frac{3}{5}[/tex]
[tex]P(\frac{B}{A})=\frac{1}{6}[/tex]
[tex]\because P(\frac{B}{A})= \frac{P(A\cap B)}{P(A)}[/tex]
[tex]\implies \frac{P(A\cap B)}{P(A)} = \frac{1}{6}[/tex]
[tex]\frac{P(A\cap B)}{\frac{1}{2}}=\frac{1}{6}[/tex]
[tex]2P(A\cap B) = \frac{1}{6}[/tex]
[tex]\implies P(A\cap B) = \frac{1}{12}[/tex]
Now,
[tex]P(\frac{A}{B})=\frac{P(A\cap B) }{P(B)}= \frac{1/12}{3/5}=\frac{5}{36}[/tex]
