Answer:
The flux of the electric field through the surface is 3.24\times10^{3}\ Nm^/C[/tex].
Explanation:
Given that,
Area of cube = 48 cm²
Charge = 28.7 nC
We need to calculate the flux of the electric field through the surface
Using formula Gauss's law
The electric flux through any closed surface,
[tex]\phi =\dfrac{q}{\epsilon_{0}}[/tex]
Where, q = charge
Put the value into the formula
[tex]\phi=\dfrac{28.7\times10^{-9}}{8.85\times10^{-12}}[/tex]
[tex]\phi =3.24\times10^{3}\ Nm^/C[/tex]
Hence, The flux of the electric field through the surface is 3.24\times10^{3}\ Nm^/C[/tex].
