Answer:[tex]\Delta E=2.0715\times 10^{-21} J[/tex]
Explanation:
Given
Temperature of the gas is increased from 100 to 200
Also we know that average kinetic energy of the molecules is
[tex]E=\frac{3}{2}\cdot \frac{R}{N_A}T[/tex]
Where
R=Gas constant
[tex]N_A[/tex]=Avogadro's number
T=Temperature in kelvin
[tex]\frac{R}{N_A}=1.381\times 10^{-23}[/tex]
So kinetic energy increases by
[tex]\Delta E=\frac{3}{2}\times 1.381\times 10^{-23}\left ( 200-100\right )[/tex]
[tex]\Delta E=2.0715\times 10^{-21} J[/tex]
