Answer:
Density of oil will be 897.292 kg[tex]m^3[/tex]
And specific gravity of oil will be 0.897
Explanation:
We have given density of oil is 1.74 slugs/[tex]ft^3[/tex]
We have to convert this slugs/[tex]ft^3[/tex] into kg/[tex]m^3[/tex]
We know that 1 slugs = 14.5939 kg
So 1.74 slug = 1.74×14.5939 = 25.3933 kg
And 1 cubic feet = 0.0283 cubic meter
So [tex]1.74slug/ft^3=\frac{1.74\times 14.5939kg}{0.0283m^3}=897.292kg/m^3[/tex]
Now we have to calculate specific gravity it is the ratio of density of oil and density of water
We know that density of water = 1000 kg/[tex]m^3[/tex]
So specific gravity of water [tex]=\frac{897.292}{1000}=0.897[/tex]
