Respuesta :

Step-by-step explanation:

Let's consider C is a matrix given by

[tex]\left[\begin{array}{ccc}a&b&c\\d&e&f\\g&h&i\end{array}\right][/tex]

them determinant of matrix C can be written as

[tex]\begin{vmatrix}a & b & c\\ d & e & f\\  g & h & i \end{vmatrix}\ =\ 4.....(1)[/tex]

Now,

[tex]det (C+C)\ =\ \begin{vmatrix}a & b & c\\ d & e & f\\  g & h & i \end{vmatrix}\ +\ \begin{vmatrix}a & b & c\\ d & e & f\\  g & h & i \end{vmatrix}[/tex]

                  [tex]=\ \begin{vmatrix}2a & 2b & 2c\\ 2d & 2e & 2f\\  2g & 2h & 2i \end{vmatrix}[/tex]

                   [tex]=\ 2\times 2\times 2\times \begin{vmatrix}a & b & c\\ d & e & f\\  g & h & i \end{vmatrix}[/tex]

                   [tex]=\ 8\times 4\ \ \ \ \ \ \ \         from\ eq.(1)[/tex]

                    = 32      

Hence, det (C+C) = 32