Respuesta :
Answer:
(a). The velocity of the object is -2.496 m/s.
(b). The total distance of the object travels during the fall is 23.80 m.
Explanation:
Given that,
Time = 1.95 s
Distance = 23.5 m
(a). We need to calculate the velocity
Using equation of motion
[tex]s = ut+\dfrac{1}{2}gt^2[/tex]
Put the value into the formula
[tex]-23.5=u\times1.95+\dfrac{1}{2}\times(-9.8)\times(1.95)^2[/tex]
[tex]u=\dfrac{-23.5+4.9\times(1.95)^2}{1.95}[/tex]
[tex]u=-2.496\ m/s[/tex]
(b). We need to calculate the total distance the object travels during the fall
Using equation of motion
[tex]v = u+gt[/tex]
Put the value in the equation
[tex]-2.496=0-9.8\times t[/tex]
[tex]t =\dfrac{2.496}{9.8}[/tex]
[tex]t=0.254\ sec[/tex]
The total time is
[tex]t'=t+1.95[/tex]
[tex]t'=0.254+1.95[/tex]
[tex]t'=2.204\ sec[/tex]
We need to calculate the distance
Using equation of motion
[tex]s = ut+\dfrac{1}{2}gt^2[/tex]
Put the value into the formula
[tex]s=0+\dfrac{1}{2}\times9.8\times(2.204)^2[/tex]
[tex]s=23.80\ m[/tex]
Hence, (a). The velocity of the object is -2.496 m/s.
(b). The total distance of the object travels during the fall is 23.80 m.
