A force F=(cx-3.00x2)i acts on a partical as theparticle
moves along an x axis, with F in newtons, x in meters andc a
constant..At x=0, the paricle's kinetic energy is 20.0 J;atx=3.00m
it is 11.0 J......FIND c...

Respuesta :

Answer:

The value of 'c' is 4.

Explanation:

We know from the basic relation between work and force is

[tex]W_{2}-W_{1}=\int_{x_{1}}^{x_{2}}F\cdot dx[/tex]

Now since the energy of the particle changes from 20 Joules to 11 Joules  as position changes from  x=0 to x=3.00 thus applying the given vales in above relation we get

[tex]11-20=\int_{0}^{3}(cx-3x^{2})\cdot dx\\\\-9=[\frac{cx^2}{2}]_0^3-[\frac{3x^3}{3}]_0^3\\\\-9=\frac{9c}{2}-27\\\\4.5c=18\\\\\therefore c=4[/tex]