Answer:
B) n=5
Explanation:
We call the initial value Xo. We start to double this initial value
X1=2*Xo n=1
We double again:
X2=2*X1=2*(2Xo) n=2
X2=2*X1=2^2*Xo n=2
In general:
Xn=(2^n)*Xo
If we want to reach a value 32 times its initial value:
2^n=32
then: n=5
2^5=2*2*2*2*2=32