Answer:
a) 30.726m/s and b) 5.5549s
Step-by-step explanation:
a.) What was Chris Huber’s speed in meters per second(m/s)?
Given the distance and time, the formula to obtain the speed is
[tex]v=\frac{d}{t}[/tex].
Applying this to our problem we have that
[tex]v=\frac{200m}{6.509s}= 30.726m/s[/tex].
So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.
b) What was Whittingham’s time through the 200 m?
In a) we stated that [tex]v=\frac{d}{t}[/tex]. This formula implies that
First, observer that [tex]19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s[/tex].
Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, [tex]v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.[/tex]
Then, applying 1) we have that
[tex]t=\frac{200m}{36.003m/s}=5.5549s.[/tex]
So, Sam Whittingham’s time through the 200 m was 5.5549s.