Answer:
q = -7.691 × [tex]10^{-13}[/tex] C
so magnitude of charge is 7.691 × [tex]10^{-13}[/tex] C
and negative sign mean charge is negative potential
Explanation:
given data
electric potential = −2.36 V
distance = 2.93 mm = 2.93 × [tex]10^{-3}[/tex] m
to find out
What are the sign and magnitude of a point charge
solution
we know here that electric potential due to charge is
V = [tex]k\frac{q}{r}[/tex] ..............................1
here k is coulomb force that is 8.99 ×[tex]10^{9}[/tex] Nm²/C² and r is distance and q is charge and V is electric potential
put here all value we get q in equation 1
V = [tex]k\frac{q}{r}[/tex]
-2.36 = [tex]8.99*10^{9} \frac{q}{2.93*10^{-3}}[/tex]
q = -7.691 × [tex]10^{-13}[/tex] C
so magnitude of charge is 7.691 × [tex]10^{-13}[/tex] C
and negative sign mean charge is negative potential
